#20 new
Nicolai C. Nielsen

leftImage and rightImage property of TableViewRow ain't working with remote pictures

Reported by Nicolai C. Nielsen | April 16th, 2011 @ 05:04 PM

When I set the leftImage and rightImage property to a remote picture (ex: leftImage: "http://www.google.com/ig/images/weather/sunny.gif") it won't show the picture.

Though when I change the SDK version of my mobile project to 1.2.0 it works ?

The 1.6.0 and 1.6.1 SDK ain't showing the remote pictures.

This code is from the example "Using TableViews" on the wiki page.

The app example pictures in the tutorial shows the pictures just fine, but with newer SDK's it doesn't.

var defaultColor = "#035385";
var window = Titanium.UI.createWindow({
  backgroundColor:'#999'
});
var weatherData = [
  { title: "Mountain View (North America)\nCloudy", leftImage: "http://www.google.com/ig/images/weather/cloudy.gif" },
  { title: "Washington, DC (North America)\nMostly Cloudy", leftImage: "http://www.google.com/ig/images/weather/mostly_cloudy.gif" },
  { title: "Brasilia (South America)\nThunderstorm", leftImage: "http://www.google.com/ig/images/weather/thunderstorm.gif" },
  { title: "Buenos Aires (South America)\nClear", leftImage: "http://www.google.com/ig/images/weather/sunny.gif" },
  { title: "Sucre (South America)\nMostly Cloudy", leftImage: "http://www.google.com/ig/images/weather/mostly_cloudy.gif" },
  { title: "London (Europe)\nOvercast", leftImage: "http://www.google.com/ig/images/weather/cloudy.gif" },
  { title: "Moscow (Europe)\nPartly Cloudy", leftImage: "http://www.google.com/ig/images/weather/partly_cloudy.gif" },
  { title: "Prague (Europe)\nClear", leftImage: "http://www.google.com/ig/images/weather/sunny.gif" },
  { title: "St Petersburg (Europe)\nSnow", leftImage: "http://www.google.com/ig/images/weather/snow.gif" },
];
// Row styling properties
for(var i=0, ilen=weatherData.length; i<ilen; i++){
  var thisObject = weatherData[i];
  thisObject.backgroundImage = "images/tableviewrow-bg.png";
  thisObject.color = defaultColor;
  thisObject.backgroundSelectedImage = "images/tableviewrow-bg-selected.png";
  thisObject.selectedColor = "black";
  thisObject.height = 75;
}
var headerLabel = Ti.UI.createLabel({
  backgroundColor:defaultColor,
  color:"white",
  font:{ fontSize: 16, fontWeight:"bold" },
  text:"The Weather App",
  textAlign:"center",
  height:35,
  width:320
});
var footerLabel = Ti.UI.createLabel({
  backgroundColor:defaultColor,
  color:"white",
  font:{ fontSize:10 },
  text:"[data and icons supplied by Google Weather API]",
  textAlign:"center",
  height:25,
  width:320
});
var table = Ti.UI.createTableView({
  backgroundColor:"white",
  data: weatherData,
  headerView:headerLabel,
  footerView:footerLabel,
  separatorColor:"white",
  top:10,
  width:320
});
window.add(table);
window.open();

Comments and changes to this ticket

  • Tom

    Tom May 3rd, 2011 @ 04:03 AM

    Hi.

    There seems to be a way to do this without using leftImage (which does not work for me too).
    When you create your rows, add then a Titanium.UI.createImageView. Such as something like this :

    var tableData = [];

        // Row styling properties
    for(var i=0, ilen=arrData.length; i<ilen; i++){
      var thisObject = arrData[i];
      thisObject.indentionLevel = 2; // To indent the text so the image shoes well

      var myRow = Titanium.UI.createTableViewRow(thisObject);
      var myImageView =  Titanium.UI.createImageView({
            image:thisObject.image,
            width:'25',
            height:'25',
            left:0
        });
      myRow(myImageView);

      tableData.push(ligne);
    }


    var table = Titanium.UI.createTableView({
      backgroundColor:"white",
      data:tableData,
      top:10,
      width:"500"
    });

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